A student obtained 20% of marks and failed by 50 marks from passing marks another student obtained 40% marks and get 30 marks more than the passing marks Find the total marks in exam:
- 500
- 450
- 300
- 400
Explanation
let the maximum marks be x
Candidate A score = 20% of x
= 20/100 (x)
=> x/5a
Candidate fails by 50 marks
Hence , candidate would have passed if 50 marks are added to his marks :
x/5 +50 => (x+250)/5
Now, score of Candidate B
40% of x
=> 40/100 (x) =>2x/5
A.T.Q
2xs/5 - 30
=> (2x-150)/5
both the equations are equal as both the equations justify minimum passing marks
Hence, (x+250)/5 = (2x-150)/5
cancelling 5 from both sides
x+250 = 2x - 150
x = 400
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